CSEC Mathematics Past Paper May 2021 Question 3 a

 CSEC Mathematics Past Paper May 2021 Question 3 a https://youtu.be/j8PnktjBll4?si=1K519PwCPpMB2y0g

CSEC Mathematics May 2021 Question 1 a b c

 CSEC Mathematics May 2021 Question 1 a b c

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May 2023 Question 6 CSEC Mathematics Past Paper Solution

 May 2023 Question 6 CSEC Mathematics Past Paper Solution

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May 2023 Question 5 CSEC Mathematics Past Paper Solution

 May 2023 Question 5 CSEC Mathematics Past Paper Solution

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May 2023 Question 4 CSEC Mathematics Past Paper Solution

 May 2023 Question 4 CSEC Mathematics Past Paper Solution
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May 2023 Question 3c CSEC Mathematics Past Paper Solution

May 2023 Question 3c CSEC Mathematics Past Paper Solution
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May 2023 Paper 2 CSEC Mathematics Question 3 a

May 2023 Paper 2 CSEC Mathematics Question 3 a

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May 2023 Paper 2 CSEC Mathematics Question 1 c

 May 2023 Paper 2 CSEC Mathematics Question 1 c
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CSEC Mathematics January 2024 Question 1 b in Jamaican Patois

CSEC Mathematics January 2024 Question 1 b in Jamaican Patois
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CSEC Mathematics January 2024

CSEC Mathematics January 2024 Question 1 a in Jamaican Patois.

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CSEC Mathematics January 2024

 

CSEC Mathematics January 2024 Introduction in Jamaican Patois

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Based Assessment (SBA) for CSEC Mathematics

 Based Assessment (SBA) for CSEC Mathematics

The videos below are of me reading sections of the CSEC Mathematics syllabus that address the SBA.

Have you started your SBA as yet? Have you chosen your topic as yet? What topic are you researching?

CSEC Mathematics Past Paper May 2022 Question 2 Solutions

Watch the video below for the solutions to the entire CSEC Mathematics May 2022 Past Paper.

Look at each of the images below. I recorded the video above and placed some images of screenshots of parts of those videos as images below. These images and notes below may enhance the learning process for some students. 

Figure 1

Tell me, in the comments below, what you think I did in figure 1 above. I will type in my own comments here after some time.

CSEC Mathematics Past Paper May 2022 Question 1 Solutions

CSEC Mathematics May 2022 past paper Question 1. Topic: Fractions

Question 1 a.

Download the past paper at

https://drive.google.com/file/d/1brXJs0qNrbMXA77jZS-S2Ek8sjF6hVET/view?usp=sharing

Watch the video below for the solutions to the entire paper. I recorded this video and placed some images of screenshots of parts of those videos below. These images and notes below may enhance the learning process for some students. 

 https://youtu.be/SVKU5MaVZRc

Take a look at this question. Part a. Topic: Fractions

Figure 1

Remember that you must do the multiplication before you carry out the addition. This is from the order of operations. This is 1/6 divided by 2/9. You will have multiply the 1/6 by the reciprocal of the denominator fraction, which is 2/9. This becomes 1/6 times 9/2 as shown below.

Figure 2

Work it out and see what you get.

 

 

Figure 3

The 3 over 3 is equal to 1. The denominators multiply together and the denominators also multiply together. You get 3 divided by 4 for that part of the question.

Figure 4

The calculation now employs the common denominator method. You could also use the LCM method but remember that the LCM method is derived from the common denominator method.

Figure 5

The LCM method of adding 7/8 to 6/8 is now shown in the diagram below. Remember, this is the same as 7 * (1/8) + 6 * (1/8). 7 + 6 = 13 so there are 13 of the (1/8).

Figure 6

The next image shows that the fractions could be worked out by drawing circles to represent the whole item, then cutting it up into equal parts. Each equal part is represented by sectors of equal angles in the circle. Each circle is cut into eights. Each shaded sector is to be counted and placed as the numerator of the fraction, while the denominator is 8, the number of equal parts. Note that three quarters is the same as six eights.

Figure 7

We now obtain the answer, which is thirteen eights.

 

Figure 8

 

We now look at part a b i of the question. It asks you to simplify 8 divided by the cube of 0.4. You may use a calculator to do it but I will work it out in a different way.

 

 

 

Figure 9

 

Note that 0.4 is equal to 4 divided by 10. When you cube this, you get (4/10) times (4/10) times (4/10).

 

Figure 10

 

 

Figure 11

 

 

Figure 12

 

4/10 is equal to 2/5 when you divide both numerator and denominator by 2. I use 2/5 in the calculation. The image below shows this, and you get 8 divided by (8/125). When you have a number divided by a denominator and the denominator is a fraction, you must multiply the number by the reciprocal of the fraction. This gives you 8 times (125)/8. The result is 125.

 

 

Figure 13

 

Now, look at the next part of the question.

 

Figure 14

 You cannot subtract the numbers 26.8 and 2.5 as yet. You have to work out the square root of 26.8 and 2.5 raised to the power of 3/2 first.

Figure 15

Look at the image above. The question says that children go to a Rodeo camp during the Easter holiday. Ms. Rekha buys bananas and oranges for the children at the camp. Bananas cost $3.85 per kg. Ms. Rekha buys 25 kg of bananas and receives a discount of 12%. You must find out how much money she spends on bananas.

 To answer the question, you must multiply the cost per kg of bananas by the mass of bananas. This results in $96.25. With a 12 percent discount, you have to find 12 percent of the cost and then subtract that from the cost.

Figure 16

The amount left after the 12 % discount is $84.70.

Figure 17

You can also consider that if you get 12 percent off the price of $96.25, then that leaves 

100 % - 12 % = 88 % percent. Find 88 percent of the cost. This leaves $84.70.

Figure 18

Now look at the next part of the question in the image above. It says that Ms. Rekha spends $165.31, inclusive of sales tax of 15% on oranges. Calculate the original price of the oranges. 

A much easier case to calculate is when you are given the price before tax, then calculate the tax and add it. In the case presented here, you are given the total cost to include tax, and then you have to calculate what the price was before the tax was added. 

A common mistake that students make is to find 15% of the price that has the tax, and the subtract. However, this is incorrect. The price before and after tax are different amounts of money, and 15% of two different amounts are different figures. 

The way how I show this in the figure above is to use x to represent the price before tax, since this figure is not known. Whatever x is, we find 15% of it. The tax is 15/100 *  x. The total amount is 

x + 15/100 * x.  This is equal to 165.31. 

Figure 19

Follow the steps in the figure above. The calculations result in the answer $143.75

Figure 20

The next part of the questions says that the ration of the number of bananas to the number of oranges is 2:3. Furthermore, there are 24 more oranges than bananas. You are required to calculate the number of bananas that Ms. Rekha bought. Using Or to represent the number of oranges and B to represent the number of bananas, I divide them as Or/B and equate this to 2/3. Then, since the number of Oranges is 24 more than the number of bananas, then Or - B = 24. These make a pair of simultaneous equations, as shown in figure 20 above. 

Figure 21

I multiply both sides by B as shown in figure 21 above. After that, I equate both values of Or.

Figure 22

Figure 22 shows that Or is equal to 2/3 B and 24 + B, therefore 2/3 B must be equal to 24 + B. 

Figure 23

I simplified to get 3B = 72.

Figure 24

Dividing both sides by 3 yields B = 24 as shown in figure 24 above.